ALGEBRA HELP! |
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ALGEBRA HELP! |
Feb 21 2005, 04:04 PM
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#1
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Senior Member ![]() ![]() ![]() Group: Member Posts: 82 Joined: Feb 2005 Member No: 97,973 |
geeenkie i hate algebra
could someone help me! heres the problem Solve the given formula for the variable shown in bold. State the rstrictions if any, for the formula obtained to be meaningful. 1. S = n/2(a+1);a HELP PLEASE! come on! help me! or at least tell me if you know how to do it or not! |
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Feb 21 2005, 04:48 PM
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#2
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NO. I'm not 13. or 14. or 15. or 16. ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 4,616 Joined: Jul 2004 Member No: 30,577 |
err don't double post please. kthx.
is n a variable too? |
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Feb 21 2005, 04:54 PM
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#3
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![]() the Ray... it filters through ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 575 Joined: Dec 2004 Member No: 76,081 |
Half of n times (a + 1) or n over 2 times (a + 1)? And what kinda math are you in?
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Feb 21 2005, 04:55 PM
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#4
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baker o.O ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 446 Joined: Feb 2005 Member No: 97,190 |
this seems like precalc stuff haha i passed algebra 2 with an a and have never seen any of this
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Feb 21 2005, 09:17 PM
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#5
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![]() hi. call me linda. ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Official Member Posts: 8,187 Joined: Feb 2004 Member No: 3,475 |
Hmm, is that the formula for the sum of numbers in an arithmetic sequence? Yeah, that looks like precal stuff. Hmm, I don't really get what you're asking though.
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Feb 22 2005, 01:02 AM
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#6
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![]() hi, my name is hillary ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 352 Joined: Dec 2004 Member No: 76,591 |
all you gotta do is get a by itself by doing the opposite to both sides.. (does that even make sense?)
here: S = n/2(a+1) multiply by two on the right sides to get rid of the two. 2s=n(a+1) then you divide by n to get rid of the n... 2s/n=a+1 then subtract 1 2s-1/n=a <----and that's your a. i hope that's what you're asking for. if not, then sorry. |
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Feb 22 2005, 05:00 PM
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#7
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Senior Member ![]() ![]() ![]() Group: Member Posts: 82 Joined: Feb 2005 Member No: 97,973 |
its alegbra 1.....
also thanks ^^ for helping! |
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| *wind&fire* |
Feb 23 2005, 08:20 PM
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#8
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Guest |
the asymtope is at a=-1
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Feb 23 2005, 08:27 PM
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#9
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boa loyal fans 4eva!!!! ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 533 Joined: Feb 2005 Member No: 100,738 |
taking calculus AP
and look at 1. S = n/2(a+1);a want to said uhm...how u do it? whis is there 2 variable n and a? |
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| *tweeak* |
Feb 23 2005, 08:30 PM
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#10
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Guest |
yeeaaaaaah ive taken alg1 and am currently in alg2, yet i have no idea what youre trying to do there
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| *xcaitlinx* |
Feb 23 2005, 08:44 PM
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#11
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Guest |
S = n/2(a+1) [like someone mentioned above...multiply both sides by 2 to cancel it out]
2s = n(a+1) now u have to do the parentheses [n x a + n x 1 (n)] 2s = na + n i think that's it.... |
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Feb 25 2005, 12:01 PM
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#12
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Senior Member ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 1,746 Joined: Oct 2004 Member No: 52,931 |
QUOTE Solve the given formula for the variable shown in bold. State the rstrictions if any, for the formula obtained to be meaningful. 1. S = n/2(a+1);a i'm assuming that the (a+1) is in the denominator along with the 2.. if i misinterpreted the problem, please correct me. Part One: Solving for 'a' really, this is quite simple, people. 1. Distribute the denominator: S = n/(2a+2) 2. Multiply both sides by the denominator (2a+2) S(2a+2) = n 3. Divide both sides by S. 2a+2 = n/S 4. Subtract 2 from both sides. 2a = (n/S) - 2 5. Divide both sides by 2. a = (n/2s) - 1 Thus... you solved for the variable 'a,' right? this doesn't involve calculus at all, does it? i'm very confused. anyway... Part Two: Restrictions Since 2S is the denominator on the right side and the denominator cannot be zero, the set of 'S' would be all real numbers except zero. S =/= 0 |
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Feb 28 2005, 04:13 PM
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#13
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Senior Member ![]() ![]() ![]() Group: Member Posts: 82 Joined: Feb 2005 Member No: 97,973 |
ok...i got my grade back..perplexism was right..thanks guys
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| *tweeak* |
Feb 28 2005, 06:04 PM
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#14
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Guest |
topic closed
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