HELP, please i have a test tomorrow - - |
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HELP, please i have a test tomorrow - - |
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#1
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![]() [[one piece :D ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 2,722 Joined: Jan 2004 Member No: 795 ![]() |
so mr/mrs math please help me on this. i have a test tomorrow. and if you can help me figure this out i'll be your slave for one day or anything. pleaseeee~
![]() ok this is what i need to know. i need to know how to convert y=mx+b into (y2-y1)=m(x2-x1) and then (ax+by)=c basicly it's slope-intercept form into point-slope form and then standard form PROBLEM : slope 2; y-intercept 5 please all the smart people that knows good math help me on this, and i'll be your slave for one day ![]() ![]() PLEASE ![]() |
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#2
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![]() Quand j'étais jeune... ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Staff Alumni Posts: 6,826 Joined: Jan 2004 Member No: 1,272 ![]() |
I think this website or this cheat sheet might help.
Just look around online. There are a lot of examples that may help you study. |
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#3
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![]() :hammer: ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Staff Alumni Posts: 9,849 Joined: Mar 2004 Member No: 7,700 ![]() |
I just reread this right now and find out that it's REALLY confusing. But it took me awhile to type it so blah. Meh. What are you taking right now?
Y = mx + b Y is the Y, m is the slope, x is x, and be is the y intercept. If they give you the equation Y = mx + b, they give you the slope and the y-intercept. You can already find another point on the line by using the the y-intercept and slope. The y-intercept already gives you a point..>> (0, y) (y2 - y1) = M (x2 - x1) ^ To find another point. So when you have y2-y1 = m(x2-x1), you substitute in your two points. A point would be (x1, y1) and (x2, y2) Okay so you found the two points, LETS PRETEND they're uhm (4, 1) and (6,3). to get them into (ax+by=c) form, you have to substitute them. Soo substituing them, you would receive two equations because there are two points. First equation >> 4a+ 1b = c ---- Now you have a system of equations! =o Second equation >6a + 3b = c To solve the system of equations, multiply the first equation by (-3) -12a + -3b = -3c 6a + 3b = c Now add them. Straight down. To get one equation.. -6a = -2c << Divide (-2) by both sides To get.. 3a = c Now, go back to the FIRST equation. 4a + 1b = c Substitute C 4a + 1b = 3a Solve the equation. Substract 3a from both sides, a + b = 0 Change ^ that to (b = -a) Uhm.. and your original equation ax + by = c Substitute. B and C ax + (-a)y = 3a Divide all sides by A. x + (-y) = 3 There's an easier way to do it I think.. because m = -a/b but uhm yeah. Got the last part (ax + by = c) from this one page.. |
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#4
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![]() [[one piece :D ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 2,722 Joined: Jan 2004 Member No: 795 ![]() |
thanks eve and loan, you two are such a awesome poop to me.
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