how do you hide the next 5 link? Options

[asian x h0ng]

how do you hide the next 5 link?

[*digital.fragrance*]

CODE

<!-- begin code provided by createblog.com -->
<script type="text/javascript">
//
// &copy; EasterEgg, http://www.xanga.com/easteregg
//
// For use at Xanga only.
//
// This script replaces any given word or text fragment with
// whatever you want: new words and fragments, or even HTML!
//
// Actually it's pretty simple: add the words or fragments you
// wish to replace to the array "oldWords" (each word placed
// between double quotation marks, and separated by colons as you
// can see below) and add their replacements to the array "newWords",
// at the same position as the original words in "oldWords".
// The example is pretty self-explaining.
//
// The script is case sensitive, meaning that if you add "something"
// to "oldWords" array it will not recognize "SOMETHING", or "SoMetHInG".
//
// You can adjust the existing arrays in this code as you see fit,
// as long as both arrays keep the same size (same amount of words
// in both arrays), otherwise a script error will occur.
//
// Copy this entire code and paste in the webstats box at your
// Look and Feel page.
//
// You're free to use this script as long as this comment remains intact,
// and as long you won't use it to cripple the comments of your visitors;
// after all, no one likes his/her words getting twisted...
//
function replaceWords()
{
    // ***add the words or fragments you wish to replace below
    var oldWords = new Array(
        "Next 5",
"Previous 5");

     // *** add the replacing words or fragments below
    var newWords = new Array(
"",
"");

    allTableData = document.getElementsByTagName('td');
    allTableHeaders = document.getElementsByTagName('th');
        
    var collections = new Array(allTableData,allTableHeaders);
    
    for (var k = 0; k < collections.length; ++k )
    {
        for (var i = 0; i < collections[k].length; ++i )
        {  
            if (collections[k][i].innerHTML.indexOf('TABLE') == -1)
            {
                for ( var n = 0; n < oldWords.length; ++n )
                {
                    var indx = collections[k][i].innerHTML.indexOf(oldWords[n])
                    while (indx != -1)
                    {  
                        var replacement = '';
                        indx = collections[k][i].innerHTML.indexOf(oldWords[n]);
                        replacement = collections[k][i].innerHTML.replace(oldWords[n], newWords[n]);
                        collections[k][i].innerHTML = replacement;
                        break;                    
                    }
                }
            }
        }
    }
}
replaceWords();
</script>
<!-- end code provided by createblog.com -->