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Math Game!, whoot!
*Girthy*
post Apr 24 2006, 12:34 AM
Post #26





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Two hydrogen atoms bumped into each other recently.
One said: "Why do you look so sad?"
The other responded: "I lost an electron."
Concerned, One asked "Are you sure?"
The other replied "I'm positive."
 
*salcha*
post Apr 24 2006, 12:35 AM
Post #27





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laugh.gif laugh.gif laugh.gif

Only two people have A's in my chem class though.
 
*Girthy*
post Apr 24 2006, 12:41 AM
Post #28





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Q. If a bear in Yosemite, and one in Alaska fall into water, which one would dissolve faster?
A. The bear in Alaska because it's polar.


A neutron walks into a bar, sits down and asks for a drink. Finishing, the neutron asks "How much?"
The bartender says, "For you, no charge."
 
*mipadi*
post Apr 24 2006, 12:50 AM
Post #29





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Hey, let's keep it clean. Stop using Hoare semantics in the math thread.
 
*wind&fire*
post Apr 24 2006, 01:27 AM
Post #30





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for trig lovers...

Consider the geometris series 1 - tan^2Θ - tan^4Θ - ...

When the limiting sum exists find its value in simplest form.

for what values of Θ in the intervel -(π/2) < Θ < π/2 does the limiting sum of a series exists


YOU CAN DO EEEEEETTTTTT!!!!
 
*mipadi*
post Apr 24 2006, 02:19 PM
Post #31





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That sounds suspiciously like your math homework!
 
GREASEbaby
post Apr 24 2006, 05:23 PM
Post #32


What's my name? Janette. and ily. <3
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Group: Member
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^x2, er, 5.

multiply by 25a(to the third power)b(to the fourth power)-83a(to the third power)
 
*Girthy*
post Apr 24 2006, 05:34 PM
Post #33





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Programming is like sex:
One mistake and you have to support for a lifetime.
 
*wind&fire*
post Apr 24 2006, 08:56 PM
Post #34





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QUOTE(mipadi @ Apr 25 2006, 5:19 AM) *
That sounds suspiciously like your math homework!

it sounds suspiciously like a question from my HSC maths exam.... spent a good ten mintues on that question... then gave up and went onto another question...

say when did you become head staffer?
 
*salcha*
post Apr 24 2006, 11:31 PM
Post #35





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1 - tan^2Θ - tan^4Θ - ...

tan2Θ = (2tanΘ)/1-tan^2Θ
tan4Θ = (tan2Θ+tan2Θ) = ((2tanΘ)/(1-tan^2Θ))+((2tanΘ)/(1-ta^62Θ))/1-(2tanΘ)/(1-tan^2Θ)(2tanΘ)/(1-tan^2Θ)

....

If anyone is willing to solve.
 
*mipadi*
post Apr 24 2006, 11:58 PM
Post #36





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QUOTE(wind&fire @ Apr 24 2006, 9:56 PM) *
say when did you become head staffer?

Someone forgot to lock the back door and I snuck in.






Seriously, though, I think it was around the end of March.
 

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