graphing inequalities, grrr ]= |
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graphing inequalities, grrr ]= |
| *xcaitlinx* |
Feb 23 2005, 08:56 PM
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#1
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Guest |
ok ... so we've been preparing for the gepa for the last couple of months. my math teacher has been trying to cover everything we've learned from 5th grade and up...so when he tried to explain this [rather quickly], i didnt quite get it.
If the value of y-coordinate is 16, what value of the x-coordinate would make the inequality y < 5x - 3 true? a. 1 b. 2 c. 3. d. 4 could someone please explain how to get the answer? im rather confused... |
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Feb 23 2005, 09:01 PM
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#2
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NO. I'm not 13. or 14. or 15. or 16. ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 4,616 Joined: Jul 2004 Member No: 30,577 |
you just treat it like a regular equation at first, so then it would be
19 < 5x (because you added 3 to both sides) then you divide by 5 on both sides and you'll get 19/5 < x 19/5 is also 3.8. now 3.8 is only less than one of those choices, 4. |
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| *xcaitlinx* |
Feb 23 2005, 09:03 PM
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#3
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thank you =D
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