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help!
pAtRiCk_sTar
post Dec 7 2004, 11:31 PM
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jellyfishing, jellyfishing
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aaacch i don't get this math problem, i'm really stupid. it's a junior high problem, so maybe someone could help?

Claire finished her assignment early, so her teacher suggested that she find the last digit of the product 3 x 3 to third power x 3 to fifth......x 3 to nineteenth. The entire product was too big for her calculator, but she still found the last digit. What is the last digit? Explain how she determined her answer

i know that if you add all the exponents, you'll get 3 to the 100th power, since
3+5+7+9+11+13+15+17+19=100 right (those are the exponent values...), so it'd be 3 to the 100th power. on my calc i got 5.153775207 to the 47th power.....what next?!?!!?

sorry if this is in the wrong board...i saw someone ask for math help awhile back, so i figured it'd be OK whistling.gif
 
 
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DaTru KataLYST
post Dec 7 2004, 11:44 PM
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白人看不懂 !!!!
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do you mean to find the last digit of the product of

(3^3)(3^5)(3^7)(3^9)(3^11)(3^13)(3^15)(3^19)

??
 

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