Chemistry question, help! |
 Nov 5 2008, 02:24 AM
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#1
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Newbie  Group: Member Posts: 8 Joined: Nov 2008 Member No: 695,844  |
Hi
I have one more question left and I have 30 minutes to do it and I can't figure it out. I would appreciate any help!! The vapor pressure of water at 25.0 C is 23.8 torr, and the heat of vaporization is 43.9 kJ/mol. What is the vapor pressure (atm) of water at 43.6C ? |
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| *Janette* |
Nov 5 2008, 01:36 PM
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#2
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this is late but whatev.
Use ln P2/P1 = - (delta H vap / R) * (1/T2 - 1/T1) P1 =23.8 torr P2 = ? T1 = 25 + 273 = 298 K T2 = 43.6 +273 = 316.6 K delta H vap = 43.9 kJ/mol R = 8.314*10^-3 kJ /mole /K By substituting above values and solving the equation P2 = 67.35 torr |
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