set to zero |
 Sep 30 2008, 08:55 PM
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#1
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 Death is a promise given to us at birth  Group: Official Designer Posts: 4,757 Joined: Mar 2004 Member No: 7,459  |
i need help with this problem. I can't seem to do it. I need to solve for "x".
Help immediately. 
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Sep 30 2008, 09:46 PM
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#2
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 in a matter of time Group: Staff Alumni Posts: 7,151 Joined: Aug 2005 Member No: 191,357 |
^ That is completely, utterly, wrong. On so many freakin' levels.
Factored: (2x-1)(2x^2-2x-1) = 0 One solution is x = 0.5. Use the quadratic formula to solve for (2x^2-2x-1) = 0 to find the other two values of x that make the whole thing = 0. |
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Posts in this topic
moorepocket set to zero Sep 30 2008, 08:55 PM
XTC 4x^3-6x^2+1=0
4x^3-6x^2=-1
10x^5=-1
50x=-1
x=-50
... Sep 30 2008, 09:43 PM Joannnnnne ^x2 Yeah, that's not right. You can't just... Sep 30 2008, 09:48 PM Gigi Actually if you have a graphing calculator (or if ... Sep 30 2008, 09:50 PM espressive 1) type it into y=
2) graph it
3) 2nd -> trace ... Sep 30 2008, 09:59 PM moorepocket everyone could use a calculator, but that's no... Sep 30 2008, 11:00 PM Gigi That's true and all, but factoring cubics is h... Sep 30 2008, 11:06 PM Joannnnnne Yeah, I remember learning this a couple years ago,... Sep 30 2008, 11:07 PM
espressive so i dug up old precalc/trig notes cause i remembe... Sep 30 2008, 11:34 PM |
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