Limits. |
 Mar 13 2006, 07:45 PM
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#1
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 Lurker.  Group: Official Designer Posts: 2,161 Joined: Feb 2004 Member No: 3,851  |
Okay. I need help. There's a quiz tomorrow, and I have no clue on what's going on. I'm sure most of you guys are pretty good in math.
For each of the following, find the limit as X approaches infinity. a] a(x)=1000/x b] b(x)=x^3-1000x^2 c] c(x)=(3x^2 + 7x)/(x^2 + 1000) How do we find the limit without a calculator? any one want to explain how limits work? Tips and tricks would be nice too. 
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| *RiC3xBoy* |
Mar 13 2006, 07:55 PM
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#2
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Just divide all values by the highest power of x and all values that are less than the highest are just zero.
a) 0 b) 1 c) 3 Here it is in more depth. For example b(x) = X^3 - 1000X^2. Now divide everything by the highest X power which is X^3. So it is now X^3/X^3 - 1000X^2/X^3 and you get 1 - 1000/x. Everything that is like 1000/x or anything that has x on the denominator is assumed to be zero, but X is approaching infinity. The answer is now just 1. |
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Posts in this topic
d4z3 Limits. Mar 13 2006, 07:45 PM
d4z3 ^ would it be the same for negative infinity? Mar 13 2006, 08:54 PM RiC3xBoy Dangit, I forgot sorry. I learned it first semeste... Mar 13 2006, 09:22 PM
mipadi Limits find a value that x approaches as x approac... Mar 13 2006, 11:19 PM |
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