math: factoring? |
math: factoring? |
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#1
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![]() Senior Member ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 4,357 Joined: Jul 2004 Member No: 28,115 ![]() |
How do you do some of these type of problems? It's my homework and I didn't really understand in class.
a^3-4a^2-a+4 or cx+cy+bx+by it's algebra 1 or algebra 2, btw. |
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#2
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![]() hi. call me linda. ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Official Member Posts: 8,187 Joined: Feb 2004 Member No: 3,475 ![]() |
Ok, you first can separate the equation the way that Gigi said:
(a^3 - 4a^2) - (a - 4). Factor out the first part: a^2(a - 4) - (a - 4) You notice that (a - 4) is a common factor of a^2(a - 4) - (a - 4), so you factor that out and get (a^2 - 1)(a - 4). And, you can then further factor the first part into (a - 1)(a + 1). |
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