+ + [[ HOMEWORK SOMEONE HELP ]] + + |
 Dec 28 2005, 10:32 PM
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#1
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 Senior Member  Group: Member Posts: 766 Joined: Nov 2005 Member No: 308,296  |
sin t = tan t cos t
is that an identity?? (cot^2)x =(csc x - 1)(cscx + 1) is that an identity?? ten q i need it in 10 minutes |
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Dec 28 2005, 10:52 PM
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#2
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 Lurker. Group: Official Designer Posts: 2,161 Joined: Feb 2004 Member No: 3,851 |
Yeah, that's right. I forgot about simplifying. >.<;;
Problem: (cot^2)x =(csc x - 1)(cscx + 1) Identity: cot^2(x)= csc^2(x) - 1 Distribute. = csc^2 +csc x-csc x - 1 = csc^2 - 1 cot^2=cot^2 It's an Identity. |
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Posts in this topic
yo pusha + + [[ HOMEWORK SOMEONE HELP ]] + + Dec 28 2005, 10:32 PM
AngelicEyz00 oh f**k, i know this. lemme refresh my memory. Dec 28 2005, 10:37 PM d4z3 I don't think any of those are Identities.
h... Dec 28 2005, 10:38 PM yo pusha ^ you can simplify though. Dec 28 2005, 10:39 PM AngelicEyz00 tanx = cosx/sinx so tanxcosx = cos2x/sinx
so brin... Dec 28 2005, 10:40 PM d4z3 Tan X = Sin X/ Cos X , Not Cos x / Sin x.
Right... Dec 28 2005, 10:43 PM AngelicEyz00 I forgot. If tanx=sinx/cosx then...
sinx=(sinx/co... Dec 28 2005, 10:45 PM AngelicEyz00 yay, we did it! lol Dec 28 2005, 10:53 PM d4z3 ahaha. Under 10 minutes...I think. Dec 28 2005, 10:54 PM
yo pusha thanks!!!!!!!!... Dec 28 2005, 11:13 PM |
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