REALLY EASY MATH, NEED HELP |
REALLY EASY MATH, NEED HELP |
| *salcha* |
Dec 6 2005, 03:29 AM
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#1
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Guest |
Okay, I lied. It's chem :E uhhh due December 7,
Doing mole problems. 1 mole of particles = 6.02 x 10^23 particles A mole of Milky Way candy bars placed end to end would reach across the Milky Way Galaxy how many times? Milk Way Galaxy = 100,000 light-years in diameter 1 light year = 5.88 × 10^12 miles So the Milky Way, in miles, would be 5.88 × 10^17 miles. Right? And a small Milky Way candy bar would be = 4.5 cm AHGNKJANB HELP. So what do I start with? EDIT; errrrrghhhhh actually, the teacher wanted me to use the big candy bar, so it's 10 cm. my bad. so this is what i have: 1 mole * 2.06x10^23 * 10 cm/10^5 * 1 light second * 1 light minute/60 light seconds * 1 light hr/60 light minutes * 1 light day/24 light hours * 1 light year/365.25 light days which amounts tooooo... 2.06x10^23/3.16x10^12 =6.52 x 10^10 ???????????? help. |
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Dec 6 2005, 07:18 PM
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#2
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dripping destruction ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Staff Alumni Posts: 7,282 Joined: Jun 2004 Member No: 21,929 |
1* 10^6 light years * 3 * 10^8 meters/ light sec * 60 *60 * 24 * 365.24 * 10 = 10 cm milky way bar lengths to go across the milky way.
take a mol, divide by that number. |
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salcha REALLY EASY MATH Dec 6 2005, 03:29 AM
wind&fire light year = 3x10^8m/s
distance of a light year =... Dec 6 2005, 03:37 AM
mzkandi Seeng as how this is due today, I will go ahead an... Dec 6 2005, 07:45 AM
salcha I updated it. Can someone check my work? Dec 6 2005, 07:11 PM
salcha errr..isn't it 10^5 light years?
arghhh and i ... Dec 6 2005, 07:29 PM
mipadi I have a really handy mole conversion program that... Dec 6 2005, 07:37 PM
salcha ):
now that, i would like.
okay, so
1 mole * 6.0... Dec 6 2005, 07:47 PM
wind&fire 3x10^8m/s = 1 light year
0.01m
0.01/3x10^8m= ho... Dec 6 2005, 07:55 PM
salcha AHH NEVERMIND I FIGURED IT OUT.
=64. yay.
close? ... Dec 6 2005, 08:12 PM![]() ![]() |