How do you solve an equotion, with 2 variables? |
How do you solve an equotion, with 2 variables? |
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#1
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![]() Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 103 Joined: Jul 2004 Member No: 31,102 ![]() |
Ah for some reason I can't remember.
I know you can substitute it but I dont' know if I'm doing it right. It's a equiangular triangle and they give the measures of the sides and I know they all equal each other I just can't get x & y 4x -y=7 2x+3y=7 Then I get kinda stuck haha.. can anyone help? You don't have to tell me the answer just like an example or whatever |
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#2
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![]() hi. call me linda. ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Official Member Posts: 8,187 Joined: Feb 2004 Member No: 3,475 ![]() |
You could also multiply the first equation by 3, and get:
12x - 3y = 21. Then, add the second equation to the first so the y cancels out: 12x - 3y = 21 - 2x + 3y = 7 ------------------ 10x = 14 Divide by 10 and you get x=7/5. Then subsitute that into one of the equations and solve for y. |
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