I need help w/ math hw, (Problem solving basically) |
I need help w/ math hw, (Problem solving basically) |
Apr 9 2005, 03:34 PM
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#1
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![]() Member ![]() ![]() Group: Member Posts: 18 Joined: Mar 2005 Member No: 117,664 |
I forgot how to figure this out
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May 7 2005, 09:34 AM
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#2
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![]() reluctantly gazing ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 472 Joined: Mar 2005 Member No: 120,555 |
QUOTE(JoeSocks @ Apr 9 2005, 4:34 PM) I forgot how to figure this out with only one variable....almost the same thing towards the end, but easier in the beginning for me because i hate using more variables than i need to. Let: x=smaller whole number 294/x=larger whole number so.... (294/x)/x=6 change to multiplication: (294/x) * (1/x) = 6 294/x^2 = 6 multiply both sides by x^2 (x squared) 294 = 6x^2 divide both sides by 6 49 = x^2 they are both perfect squares, find the square root of both: 7 = x plug it into the beginning.. x=smaller whole number ---> 7 294/x=larger whole number ---> 42 |
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JoeSocks I need help w/ math hw Apr 9 2005, 03:34 PM
racoons > you QUOTEWhat are two whole numbers whose product is 2... Apr 9 2005, 03:38 PM
KissMe2408 I would love to tell you the answer, cept i don... Apr 9 2005, 03:40 PM
autumn. yes the answer is 7 and 42, but here is the work i... Apr 9 2005, 05:29 PM
lil_nat_cat QUOTE(autumn. @ Apr 9 2005, 5:29 PM)yes the a... Apr 10 2005, 07:50 AM
suddenly she yeah. substitution is your friend.
basically, wri... Apr 9 2005, 05:45 PM
DaTru KataLYST O GOD I love substitution!! So much better... Apr 11 2005, 12:49 AM
wind&fire ^ why arent you closing this?
[edit] fageddaboudi... Apr 11 2005, 01:52 AM
ROARxD QUOTEyes the answer is 7 and 42, but here is the w... May 6 2005, 09:26 PM![]() ![]() |