algII, factoring |
 Mar 21 2005, 07:25 PM
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#1
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Senior Member  Group: Member Posts: 48 Joined: Feb 2005 Member No: 95,036  |
i'm not quite sure how to factor these..
Factor out the GCF (m-9)(m+1)+(m-9)(m+2) ^^I know i should use the grouping method.. so would it be (m+1)+(m+2)(m-9)?? orrrrr do i need an pair of brackets? [(m+1)+(m+2)](m-9) ?? m^5(r+s)+m^5(t+u) ^^grouping in that one too.. but i sorta have an idea but it may be wrong.. answer may be (m^5)(r+s)(t+u) ?? Factoring polynomials (a+b)^2-(a-b)^2 that's alll.. any help would be greatlyy appreciated. thank you. 
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Mar 21 2005, 11:41 PM
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#2
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 Word. Group: Member Posts: 3,004 Joined: Jul 2004 Member No: 34,673 |
does m( -9-1) + m(-9+2) work too? man i need to remmember this stuff too.. lol.
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Mar 22 2005, 04:40 PM
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#3
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Senior Member Group: Member Posts: 1,746 Joined: Oct 2004 Member No: 52,931 |
QUOTE(Levy2k6 @ Mar 21 2005, 11:41 PM) does m( -9-1) + m(-9+2) work too? man i need to remmember this stuff too.. lol.  nope, doesn't work. you can't exchange terms that are added or subtracted like that. |
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Posts in this topic
Freakerr algII Mar 21 2005, 07:25 PM
monde libre for factoring the GCF, the answer would be the sec... Mar 21 2005, 11:38 PM
mona lisa (m-9)(m+1)+(m-9)(m+2)--> (m+9)[(m+1)+(m+2)] ca... Mar 22 2005, 04:01 PM Freakerr ummm..
i figured out this one..
(a+b)^2-(a-b)^2
-... Mar 22 2005, 05:21 PM
salcha ^ from what i can see, the process looks correct.. Mar 23 2005, 12:54 AM |
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