math homework, help..? Options

[missmissy]

Ok, I was sick for a while and I talked to the teacher about it. He explained it to me but he is a horrible explainer so I never really got what he said. So he told me to look in the text book and I still don't get it.. Do you think you can help?

graph each system of equations using the coordinate plane provided. Then determine whether the system has one solution, no solution, or infinitely man solutions. If the solution has one, name it.

x+y=3
x-y=3

2x-y=6
4x-2y=12

x+y=0
x+y=2


Do you think you could do two of those and make a graph of it on photoshop for me? You know, like make a grid and plot the lines? I just need examples so I can figure out the rest. There is a whole sheet of the things I need to do..

[*wind&fire*]

look here ill do an example for you

4x-2y=12
since its an equation of a line then its easy...

just findthe x and y intercepts

you find the x intercept by making y=0

thus 4x-2(0)=12 ...

thus it goes to 4x=12

then x=12/4

x=3

then find the y intercept by making x=0

hence -2y=12

then y=12/-2

y=-6

thus the intercepts are at (3,0) and (0,-6)

then sketch (see bottom of post.. but i hope you fill the grpah in better than me and do it to scale)

its dodgy but it explains a whole lot... see ive done the most difficult one and the others are soo simple

then you graph it and see if they intersect. this one intersects once, so it has one solution. if they don't intersect, there's no solution. and i forgot what happens if there's many solutions.

you can only have multiple answers if its a parabola of quadratic or cubic... but these are simple line graphs and are very straight forward and have only one answer... and the line will always intersect the x and y axis unless you have the equations of y=0, x=0 or x=y