Hard Calculus Problem |
 Dec 14 2005, 06:41 PM
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#1
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 ;)  Group: Staff Alumni Posts: 9,573 Joined: Feb 2005 Member No: 99,124  |
I have no idea how to solve this problem. Our Algebra teacher said that if we can solve this problem, then we get 10 extra points on our mid term.
Let f(x) be a function defined on the positive integers such that: f(x) = x/2 if x is even f(x) = (3*x+1)/2 if x is odd |
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Dec 14 2005, 07:26 PM
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#2
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 Senior Member Group: Member Posts: 979 Joined: Aug 2005 Member No: 205,020 |
wait. what's the problem? i don't see an actual problem to do here, just a statement.
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| *RiC3xBoy* |
Dec 14 2005, 08:23 PM
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#3
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I too, do not understand the question. I suppose you want us to find a Function....but.....with what exactly?
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Dec 15 2005, 10:10 PM
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#4
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;) Group: Staff Alumni Posts: 9,573 Joined: Feb 2005 Member No: 99,124 |
That's all that she gave us. She didn't give us a number to define the function.
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Dec 17 2005, 04:27 AM
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#5
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 Senior Member Group: Member Posts: 189 Joined: Nov 2004 Member No: 63,312 |
where's the calculus in this?
also, where's the problem? lol i'm really confused. does she want you to graph it? in that case, i've attached my best guess... not sure if this is the answer, we havent really done this in calc and its very late also ive summarily forgotten all the stuff we've learned this year due to finals already being over with so THIS IS MOST LIKELY WRONG AND I'M TAKING NO RESPONSIBILITY FOR IT ITS JUST A GUESS haha sry but im being paranoid that you'll rely on my answer and itll turn out to be horribly and fudgily wrong. (the red is what the graph would be) (edit)OK JK NVM itd be the 2nd graph im attaching.. even and odd can only be integers *cry* why am i so dumb This post has been edited by anoniez: Dec 17 2005, 06:24 AM |
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| *wind&fire* |
Dec 17 2005, 08:33 AM
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#6
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for some reason it would be harder if you had some asymtopes
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Dec 17 2005, 01:29 PM
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#7
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Senior Member Group: Member Posts: 1,746 Joined: Oct 2004 Member No: 52,931 |
I think that the purpose of this problem is to find one function that fits that description.
I don't think that this is calculus, but what I would do is create a table of values like this: x f(x) 1 2 2 1 3 5 4 2 5 8 6 3 7 11 Create a table on a graphing calculator and then try to find the function. I can't find my TI-83 right now, and I don't know how to do anything practical on my TI-89 Titanium, so I can't graph it at the moment. Hm, that would probably be a very awkward graph. Good luck. 
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| *mipadi* |
Dec 17 2005, 02:14 PM
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#8
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I actually still don't get this... You have f(x) already defined in the statement.
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| *RiC3xBoy* |
Dec 17 2005, 03:18 PM
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#9
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anoniez, you got some pretty handwriting.
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Dec 17 2005, 05:05 PM
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#10
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Senior Member Group: Member Posts: 189 Joined: Nov 2004 Member No: 63,312 |
haha, thanks! lol
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| *wind&fire* |
Dec 18 2005, 09:19 PM
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#11
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oh i might as well give ita shot even if it feels wrong
f(x) = x/2 if x is even therefore f(x)=f(-x) -x/2=x/2 1=-1 f(x) = (3*x+1)/2 if x is odd f(x)=/=f(-x) wait is it three to the power of x of three to the power of x PLUS one?? |
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Dec 18 2005, 11:28 PM
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#12
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Senior Member Group: Member Posts: 189 Joined: Nov 2004 Member No: 63,312 |
QUOTE(wind&fire @ Dec 18 2005, 8:19 PM) oh i might as well give ita shot even if it feels wrong f(x) = x/2 if x is even therefore f(x)=f(-x) -x/2=x/2 1=-1 f(x) = (3*x+1)/2 if x is odd f(x)=/=f(-x) wait is it three to the power of x of three to the power of x PLUS one??  but thats if f(x) is even/odd, not if x is even/odd, right? lol its probably past the due date already.. |
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| *mzkandi* |
Dec 19 2005, 09:41 AM
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#13
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I'm going to assume this assignment has been turned in or the topic starter needs no further help, if that is not the case, pm me or another able staff member to reopen.
Topic Closed. |
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