Extra Credit helpp! |
Extra Credit helpp! |
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#1
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![]() I'm with Stupid. ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 410 Joined: Feb 2004 Member No: 4,973 ![]() |
Can someone teach me how to do these problems, please?
Determine whether A, B, and C lie on the same line (without graphing). Given A(2,2), B(-2,-6), C(6,10) Solve for N 2 n+1 = 8 { the n+1 is the exponents of 2. } PLEAASE HELP THIS WILL DO SO MUCH FOR MY GRADE. Haha. |
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*mzkandi* |
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#2
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When is the deadline for this assigment?
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#3
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![]() I'm with Stupid. ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 410 Joined: Feb 2004 Member No: 4,973 ![]() |
Tomorrow. >.<
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#4
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![]() hi. call me linda. ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Official Member Posts: 8,187 Joined: Feb 2004 Member No: 3,475 ![]() |
For the first one: You calculate the slope (Δy/Δx) between each point (between A and B, B and C and A and C). If the slope is the same, then they are all on the same line.
For 2^(n+1)=8: You know that 2^3 is 8, so you replace that for 8, thus getting 2^(n+1)=2^3. Then, because they have the same base, the powers should equal each other: n+1 = 3. You then get that n=2. |
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*brownsugar08* |
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#5
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Well Linda already helped you. No point in being repetitive.
Question answered? Topic Closed. |
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