SAT Problem |
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 May 28 2005, 06:12 PM
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#1
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 Senior Member  Group: Member Posts: 5,585 Joined: Aug 2004 Member No: 38,082  |
This problem was from my SAT test on May 7th...which I thought the problem was REALLY easy..(well it looked easy), but I couldn't get it.
The problem n is a two digit number. If n is divided by 10, the remainder is 9. Also, if n is divided by 7, the remainder is 8. What is n? All the math brainiacs....answer that one please. |
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May 28 2005, 06:28 PM
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#2
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 Quand j'étais jeune... Group: Staff Alumni Posts: 6,826 Joined: Jan 2004 Member No: 1,272 |
If the remainder is 8, wouldn't you still be able to divide?...
confused... < math stupid. |
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May 28 2005, 08:27 PM
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#3
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 Assistant Manager of Personal Group: Member Posts: 1,101 Joined: Jul 2004 Member No: 26,922 |
LMAO, i remember that problem; i just skipped it.........
what did you get? i got only a 1520 >< |
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| *nightmare4taki* |
May 29 2005, 03:55 AM
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#4
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WRONG POST
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| *Azarel* |
May 29 2005, 04:00 AM
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#5
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QUOTE(uninspiredfae @ May 28 2005, 4:28 PM) If the remainder is 8, wouldn't you still be able to divide?... confused... < math stupid. You're not stupid, Fae; the person just has the problem incorrect, although I can't remember the numbers now. But yeah, that person definitely has incorrect numbers in the original problem. |
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May 29 2005, 03:58 PM
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#6
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Senior Member Group: Member Posts: 5,585 Joined: Aug 2004 Member No: 38,082 |
Well does anyone remember the actual problem then? I know the first part is correct...can't remember the second part.
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May 29 2005, 08:41 PM
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#7
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Quand j'étais jeune... Group: Staff Alumni Posts: 6,826 Joined: Jan 2004 Member No: 1,272 |
QUOTE(Azarel @ May 29 2005, 4:00 AM) You're not stupid, Fae; the person just has the problem incorrect, although I can't remember the numbers now. But yeah, that person definitely has incorrect numbers in the original problem.  Oh... *whew*... thanks!!!! |
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| *Azarel* |
May 29 2005, 08:59 PM
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#8
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n is a two digit number. If n is divided by 10, the remainder is 9. Also, if n is divided by 9, the remainder is 8. What is n?
n/10 = x r9 n/9 = y r8 n = 89 kthx. |
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| *nightmare4taki* |
May 30 2005, 04:28 PM
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#9
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^LOL I figured something in the problem had to be incorrect because you cant get a remainder of 8 when you divide by 7. the remainder would have to be n<7.
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| *Azarel* |
May 30 2005, 07:37 PM
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#10
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QUOTE(nightmare4taki @ May 30 2005, 2:28 PM) ^LOL I figured something in the problem had to be incorrect because you cant get a remainder of 8 when you divide by 7. the remainder would have to be n<7. Hence the reason Fae was confused.
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Jun 7 2005, 08:15 PM
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#11
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 *lurks around* Group: Member Posts: 624 Joined: May 2004 Member No: 15,932 |
When you can't figure it out algebraically..just plug in random numbers until you get the desired product..
You knew it was a two digit number and that you would get a remainder of 9 if you decided it by 10. Therefore..it has to be 9 more than a two digit number that ends with 0..so go through the list. 19, 29, 39, 49, 59, 69, 29, 89..like that. Just a tip. o_O. |
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