someone solve these, please Options

[icecreamisyummy]

okay so i'm trying to get ready for a math placement test, and well last time i took algebra was...my junior year in high school. so im a little rusty but can someone solve these for me

1. (3x-2y)^2=
A. 9x^2-4y^2
B. 9x^2+4y^2
C. 9x^2-4y^2-6xy
D. 9x^2-4y^2-12xy

2. x^2-x-6/x^2-4=
A. x-3/2
B. x-3/x-2
c. x-3/x+2
D. 3/2

okay so I have the answers to them. This is suppose to be elementary algebra, and I feel dumb that I can't freaken figure out how they got the answers. Yea, those are the only ones I had trouble with. The one I'm having the most trouble with is 2. Idk, I really do feel dumb, so go ahead, say I'm dumb lol.

anyway, I'll tell you guys if youre right or wrong.
and I would like an explanatin on how to do these, specially number 2

I'm sure after I see the explanation, a light bulb with go off lol

oh and srry for posting this on here, I figured I would get more responses and get em a lot faster.

EDIT//

okay so i figured out the first one... and almost figured out the second one so can someone help!! i wanna make sure i figured it out correctly

[livwho]

2. x²-x-6/x²-4=

Answer: B

[icecreamisyummy]

#1 is B as well.

no number 1 is NOT B. thats what i thought too but it isnt.

[lojay]

Number one is A
I'm not really sure how you set up number two.. is it x squared minus x minus 6 over x squared minus 4?

If so... then number two would be B.

The key to these is pretty much foiling. [First Outer Inner Last]

For the first problem you foil (3x-2y)(3x-2y) and get 9x^2 - 6xy - 6xy + 4x^2 and that simplifies to 9x^2 + 4y^2


For the second problem you change x^2 - x - 6 to (x-3)(x+2) and change x^2 - 4 to (x+2)(x-2) and now since there is x+2 on top of the divding line and underneath it you can cancel them both out so you are left with (x-3) over (x-2).

Hope I helped...

[icecreamisyummy]

Number one is A
I'm not really sure how you set up number two.. is it x squared minus x minus 6 over x squared minus 4?

If so... then number two would be B.

The key to these is pretty much foiling. [First Outer Inner Last]

For the first problem you foil (3x-2y)(3x-2y) and get 9x^2 - 6xy - 6xy + 4x^2 and that simplifies to 9x^2 + 4y^2
For the second problem you change x^2 - x - 6 to (x-3)(x+2) and change x^2 - 4 to (x+2)(x-2) and now since there is x+2 on top of the divding line and underneath it you can cancel them both out so you are left with (x-3) over (x-2).

Hope I helped...

youre wrong about number one. it is NOT A or B

[pandamonium]

then number 1 is D. lol i havent taken trig/algebra since high school too so dont feel bad, i did them just to freshen, up i will update when i get number 2 done.

[lojay]

Oh crap. haha, my bad. Meant 9x^2 - 12xy + 4y^2

In which case, yeah, it is D. Sorry. My math was right on my paper, just read the wrong answer, haha.

[icecreamisyummy]

then number 1 is D. lol i havent taken trig/algebra since high school too so dont feel bad, i did them just to freshen, up i will update when i get number 2 done.

youre right!! about number 1, but can you explain to me how you got -12xy.

my uncle told me you multiple the inside twice or somethig like that... 3x * 2y=6xy * 2= 12xy. somethign along those lines

[pandamonium]

did i get it right?

YESSSS!!!

number one cause

it turns to be

9x^2-6xy-6xy+4y^2

then

9x^2-12xy+4y^2

cause both of the (-6xy) added together makes (-12xy)

edit............

you can combine x & y as long as they are like terms and on the same side.

[icecreamisyummy]

did i get it right?

number one cause

it turns to be

9x^2-6xy-6xy+4y^2

then

9x^2-12xy+4y^2

cause both of the (-6xy) added together makes (-12xy)

hmm okay

[lojay]

Here, I'll scan in all my work on paper so that you can see it. I'll just rewrite it first so that it isn't so confusing.

And yes, that was right pandamonium

[icecreamisyummy]

So you got both answers now?

i knew both answers already, i jstu couldnt figure out what iw as doing wrong and how i needed to solve them.

[pandamonium]

i forgot how to do fractions lMAO so imma wait till you scan the answers in. i feel so behind. good thing im taking advanced algebra next sem.

[icecreamisyummy]

i forgot how to do fractions lMAO so imma wait till you scan the answers in. i feel so behind. good thing im taking advanced algebra next sem.

i have more problems :-( .... but theres are suppose to be "college level mathematics"

i need to remember how to do this sh*t if not im gonna be stuck in intermediate algebra.and i wont be able to take anatomy. grrr

[lojay]

I hope that tag works... if not I'll edit it...
Edit// Phew. It's a bit big... but oh well. I hope that makes sense.

[icecreamisyummy]

okay i def understand number one now lol. no doubts anymore.

but number 2.. i mean i understand it, but...well kinda lol

thanks by the way everyone!

[*jeanna*]

miy heaed hurets

[*CowerPointyObjects*]

Elementary algebra? HAHAHA I've taken calculus and exempted out of college math and I can't remember how to do this shit.

[icecreamisyummy]

Elementary algebra? HAHAHA I've taken calculus and exempted out of college math and I can't remember how to do this shit.

idk if to take this as an insult or something else.

[*CowerPointyObjects*]

Why in the hell would you take it as an insult? It's just recognition of my complete and total inability to do math.

[Elba]

LMAO. Sorry, but some of you guys suck at math.

[Spirited Away]

I have a problem with how you typed up number two. If it supposed to be: (x^2-x-6)/(x^2-4)=

Then, I'd work it out like this:

[(x+2)(x-3)]/(x+2)(x-2)=
(x-3)/(x-2)

It is because both the numerator and denominator (x+2)'s cancel each other out.

I haven't touched math in 4 years so I don't know if that's right... but oh well.

[Gigi]

^ Thanks for clearing it up; that is COMPLETELY different from what she actually wrote.

And yes, I agree with Elba. Sorry if I'm being insensitive, but honestly...I don't understand why some of you can't expand #1.

[icecreamisyummy]

I have a problem with how you typed up number two. If it supposed to be: (x^2-x-6)/(x^2-4)=

Then, I'd work it out like this:

[(x+2)(x-3)]/(x+2)(x-2)=
(x-3)/(x-2)

It is because both the numerator and denominator (x+2)'s cancel each other out.

I haven't touched math in 4 years so I don't know if that's right... but oh well.

I copied it exactly from the paper...

[*CowerPointyObjects*]

To be fair, I just assumed I couldn't do it because I didn't want to think about it. I knew I could do it if I wrote it out, and I did remember how to do it as I was typing something a second ago, but I don't care enough to. I am quite terrible at math, though.

[Spirited Away]

^ Thanks for clearing it up; that is COMPLETELY different from what she actually wrote.

yea sure, I mean I didn't want to work it out because I thought it's (6/x^2)-4. That would have been a little weird and scary.

I copied it exactly from the paper...

Yea, I guess they want you to know how to group them together or something.

[EddieV]

0_0 I'm the only Asian who can't solve this T__T

[livwho]

I'm not Asian, and I solved it.

Don't feel bad.

[icecreamisyummy]

0_0 I'm the only Asian who can't solve this T__T

ahhh hahahahaha youre funny. but umm, interesting.

[kryogenix]

if you suck at them, you deserve to get them wrong and be placed in a lower math class.

[Spirited Away]

if you suck at them, you deserve to get them wrong and be placed in a lower math class.

True. You don't wanna be stuck in class you can't handle and end up getting a bad grade or having to drop.

[Sandraaa]

OMG. What the hell is this? I haven't done math in AGES.

[Simba]

Do my homework too please.

[icecreamisyummy]

if you suck at them, you deserve to get them wrong and be placed in a lower math class.

im sure if you havent done something in almost two years... youd have trouble remembering some stuff.

i had straight A's in math during highschool.

[*CowerPointyObjects*]

True. You don't wanna be stuck in class you can't handle and end up getting a bad grade or having to drop.

I always did really well on placement tests, and then horribly in the classes *shrug* It worked in college, though, because arbitrarily doing well meant no more math for me!