quadratic function, ?? |
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 Oct 18 2005, 05:48 PM
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#1
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Senior Member  Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827  |
Does anyone know how to do the quadratic function thing on the texas calculater TI-83? I dont know how to put it on it. and figure it out. One problem looks like this.
y= 3x - 2x squared + 3 I dunno how figure it out n how u put it on |
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Oct 18 2005, 05:59 PM
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#2
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 dopey alan Group: Member Posts: 215 Joined: Jun 2004 Member No: 21,260 |
go to " y = " at the top left... put in.. (-)2x^2 + 3x + 3
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Oct 18 2005, 06:00 PM
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#3
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dopey alan Group: Member Posts: 215 Joined: Jun 2004 Member No: 21,260 |
then graph. of course.
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Oct 18 2005, 06:01 PM
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#4
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Senior Member Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 |
okay thanks. Do you know how you would find the vertex of the parabola?
y= x squared + 2 - 1 |
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Oct 18 2005, 06:06 PM
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#5
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dopey alan Group: Member Posts: 215 Joined: Jun 2004 Member No: 21,260 |
the equation for that is.... negative b over 2 a?
-b/(2a) not sure... it seems like i learned that so so soo long ago. |
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Oct 18 2005, 06:07 PM
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#6
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Senior Member Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 |
but how did u figure that out I dont get it
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Oct 18 2005, 06:15 PM
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#7
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dopey alan Group: Member Posts: 215 Joined: Jun 2004 Member No: 21,260 |
lol, sorry, i dont' exactly remember... i think.. X = -b/(2a)... try that, then find y... then see if its right
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Oct 18 2005, 06:38 PM
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#8
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 Senior Member Group: Member Posts: 643 Joined: May 2005 Member No: 146,564 |
QUOTE(angelbabystar @ Oct 18 2005, 5:01 PM) okay thanks. Do you know how you would find the vertex of the parabola? y= x squared + 2 - 1  use a graphing caculator press y= then press in (xsquared)+2+1 press graph and then it graphs it for you if u want the vertex press trace and ta-da! hopefully it helps |
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| *mzkandi* |
Oct 23 2005, 03:26 PM
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#9
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Guest |
Its been a few days since the topic starter has responded and since the person left to no deadline, I will go ahead and close this.
Topic Closed. |
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