anyone really good at math?, if u can help |
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anyone really good at math?, if u can help |
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#1
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Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 ![]() |
Im doin this one paper I need to do it to pass this class and I can't figure some problems out has to do with solving equations. can anyone help?
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#2
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Senior Member ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 1,575 Joined: Jan 2005 Member No: 93,957 ![]() |
you might want to be more specific.
move to homework? |
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#3
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![]() <33 ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 2,745 Joined: Mar 2005 Member No: 114,234 ![]() |
![]() But, I guess I am a little good at Math. What grade are you in? Can be more specific? |
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*jooleeah* |
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#4
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Guest ![]() |
Moved to Homework.
![]() Could you be more specific? That way, we can help you out more. ![]() |
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#5
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Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 ![]() |
where is that sectionat
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#6
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Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 ![]() |
im in 12th and I totally forget n just cant understand this again
One problem looks like 8x-15=4x+12 |
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*jooleeah* |
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#7
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Please don't double-post
![]() Okay, hm. I'm pretty sure I know what to do. This is simple algebra. So. Your problem is....8x-15=4x+12. First, add like terms. Combine 8x + 4x. That gives you 12x. So now, the problem will be like...: 12x-15=12. Now all you have to do is add 15 to -15 and 12. Now it'll be like this. 12x=27. All you have to do is divide 12 on both sides now. I'll let you figure it out from here. ![]() Hopefully that'll help. |
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#8
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![]() "Silly me, I thought this was a free country" ![]() ![]() ![]() ![]() ![]() ![]() Group: Human Posts: 1,666 Joined: Nov 2004 Member No: 60,913 ![]() |
QUOTE(angelbabystar @ Oct 6 2005, 6:01 PM) im in 12th and I totally forget n just cant understand this again One problem looks like 8x-15=4x+12 =/ this is easy... ~first get your X terms all on one side... so subtract four x from both sides... this is what you would get: 4x-15=12 ~then... isolate the x term so add fifteen to both sides: 4x=27 ~ now you can just solve for X by dividing by four x=27/4 EDIT: the post above mine is wrong.... =/ |
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#9
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Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 ![]() |
okay thanks i understand that one now. There's another 2 other kind if you could help
2(a-8)+7=5(a+2)-3a-19 then the other one is 1 3 - d + - = -2d 2 8 |
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*jooleeah* |
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#10
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QUOTE(simx @ Oct 6 2005, 7:06 PM) =/ this is easy... ~first get your X terms all on one side... so subtract four x from both sides... this is what you would get: 4x-15=12 ~then... isolate the x term so add fifteen to both sides: 4x=27 ~ now you can just solve for X by dividing by four x=27/4 EDIT: the post above mine is wrong.... =/ CRAP you're right. Sorry. >< Eish. |
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#11
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![]() No Day But Today. ![]() ![]() ![]() ![]() ![]() ![]() Group: Member Posts: 1,405 Joined: Feb 2005 Member No: 99,184 ![]() |
QUOTE(angelbabystar @ Oct 6 2005, 6:10 PM) 1. Distribute the 2 across the parentheses and the 5 across the other pair of parenthesis 2. You get 2a-16+7=5a+10-3a-19 after you distribute. 3. Combine like-terms. I.E. add all the terms with the a after them and all the regular numbers. Remember, if you're moving a number across the equal sign, it changes signs (so if it's negative and you move it to the other side, it will be positive and vice versa). 4. You should get -6a=-18 5. Divide by -6 on both sides. 6. a= ___ 7. And there you have it! I hope that made sense... ![]() |
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#12
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Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 ![]() |
step 3 how its 2a-16+7=5a+10-3a-19
then you add like terms im a lil ehh on where 6a came from |
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#13
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![]() "Silly me, I thought this was a free country" ![]() ![]() ![]() ![]() ![]() ![]() Group: Human Posts: 1,666 Joined: Nov 2004 Member No: 60,913 ![]() |
QUOTE(angelbabystar @ Oct 6 2005, 6:10 PM) okay thanks i understand that one now. There's another 2 other kind if you could help 2(a-8)+7=5(a+2)-3a-19 then the other one is 1 3 - d + - = -2d 2 8 The first one: ~start with the distribution so... 2a - 16 +7 = 5a + 10 - 3a - 19 ~next combine the like terms 2a - 9 = 2a - 9 ~ get your "a" terms all on one side but since it'll equal zero then i'm not really sure... I dont' remember.. but the statement is true since you'll be left with -9 = -9.... but i'm not sure if it's no solution or not... #2.... I dont' understand the question... EDIT: I don't see how b0st0ngrl got her answer... it doesn't make sense to me... |
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#14
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Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 ![]() |
The other one I cant type it on here the way it looks cuz that what i tire to do n it didnt look right but its
1 over 2 *d + 3 over 8 - 2d then another is 3 over 4 *t - 5 over 4 = 1 over 3 *t |
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#15
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![]() Senior Member ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Staff Alumni Posts: 4,799 Joined: Aug 2004 Member No: 37,450 ![]() |
^ Are you making these people do your homework? =/
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#16
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Senior Member ![]() ![]() ![]() ![]() Group: Member Posts: 151 Joined: Dec 2004 Member No: 74,827 ![]() |
no I have 40 problems to do and those are 3 different kinds that I dont know how to do n ive ppl in my house n they can't help cuz they dunno how to do it
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*jooleeah* |
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#17
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Guest ![]() |
Remember, we're here to help you with homework. Not to give you answers.
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#18
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![]() hi. call me linda. ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Official Member Posts: 8,187 Joined: Feb 2004 Member No: 3,475 ![]() |
Hmm, for the second question, you subtract (1/2)d from 2d.
You then get 3/8 = 3/2 d. Then, you divide both sides by 3/2 (or multiply by the reciprocal: 2/3). The 3s cancel out, and you then get 2/8 = d. Simplify and you get d = 1/4. |
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#19
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![]() Senior Member ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Staff Alumni Posts: 4,799 Joined: Aug 2004 Member No: 37,450 ![]() |
OKay its been over two days so I'm guessing you turned it in or you don't need help anymore.
Topic Closed |
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