This problem was from my SAT test on May 7th...which I thought the problem was REALLY easy..(well it looked easy), but I couldn't get it.

The problem
n is a two digit number. If n is divided by 10, the remainder is 9. Also, if n is divided by 7, the remainder is 8. What is n?

All the math brainiacs....answer that one please.

If the remainder is 8, wouldn't you still be able to divide?...

confused...

< math stupid.

LMAO, i remember that problem; i just skipped it.........

what did you get?

i got only a 1520 ><

WRONG POST

You're not stupid, Fae; the person just has the problem incorrect, although I can't remember the numbers now. But yeah, that person definitely has incorrect numbers in the original problem.

Well does anyone remember the actual problem then? I know the first part is correct...can't remember the second part.

Oh... *whew*... thanks!!!!

n is a two digit number. If n is divided by 10, the remainder is 9. Also, if n is divided by 9, the remainder is 8. What is n?

n/10 = x r9
n/9 = y r8

n = 89

kthx.

^LOL I figured something in the problem had to be incorrect because you cant get a remainder of 8 when you divide by 7. the remainder would have to be n<7.

Hence the reason Fae was confused.

When you can't figure it out algebraically..just plug in random numbers until you get the desired product..

You knew it was a two digit number and that you would get a remainder of 9 if you decided it by 10. Therefore..it has to be 9 more than a two digit number that ends with 0..so go through the list.

19, 29, 39, 49, 59, 69, 29, 89..like that.

Just a tip. o_O.