well i have a project thats like due for this.
and i know how to find the cosines for this.. triangle. a^2 = b^2+c^2 - 2bcCOSA ( the 2's are exponents)

but i don't know how to find the sines.

a^2 = 15^2 + 55^2 – 2(15) (55) (-0.906307787)
a^2 = 225 + 3025 – (1650) (-0.91)
a^2 = 4751.5
a= 68.93

i know the formula for sin is a/sinA = b/sinB = c/sinC ( / is the division, fraction.. whatever you call it line)

so.. does anyone know how to explain or.. teach me really how to find the sin?

thank you so much.

wow we learned the sins and cosines to be ratios on a figure

you know.... sin = opposite side of angle/ hypotenuse
cosine = adjacent side of angle/ hypotenuse
tangent = opposite side / adjacent side

or does this triangle not have measures? Can you post a paint diagram

lol that's not what she means. this is tough having to do this on the computer. i used to know that. er..remember it, but i don't know where all my notes are.
ok, http://img206.exs.cx/my.php?loc=img206&image=hwhelp3ge.png

^^
haha nice drawing! and yup, thats how you do it.