yo pusha
Dec 28 2005, 10:32 PM
sin t = tan t cos t
is that an identity??
(cot^2)x =(csc x - 1)(cscx + 1)
is that an identity??
ten q
i need it in 10 minutes
AngelicEyz00
Dec 28 2005, 10:37 PM
oh f**k, i know this. lemme refresh my memory.
annalucky
Dec 28 2005, 10:38 PM
yo pusha
Dec 28 2005, 10:39 PM
^ you can simplify though.
AngelicEyz00
Dec 28 2005, 10:40 PM
tanx = cosx/sinx so tanxcosx = cos2x/sinx
so bring the sinx with the other sinx
sinx sinx = cos2x
sin2x =cos2x
is that right so far?
annalucky
Dec 28 2005, 10:43 PM
Tan X = Sin X/ Cos X , Not Cos x / Sin x.
Right?
AngelicEyz00
Dec 28 2005, 10:45 PM
I forgot. If tanx=sinx/cosx then...
sinx=(sinx/cosx)cosx
sinx=sinx
1=1?
No, I think tanx=cosx/sinx
//edit, my bad. you're right.
if it's 1=1 then it is an identity.
as for the next one: (cot^2)x =(csc x - 1)(cscx + 1)
cot2x = csc2x - 1
i'm stuck
annalucky
Dec 28 2005, 10:52 PM
Yeah, that's right. I forgot about simplifying. >.<;;
Problem: (cot^2)x =(csc x - 1)(cscx + 1)
Identity: cot^2(x)= csc^2(x) - 1
Distribute.
= csc^2 +csc x-csc x - 1
= csc^2 - 1
cot^2=cot^2
It's an Identity.
AngelicEyz00
Dec 28 2005, 10:53 PM
yay, we did it! lol
annalucky
Dec 28 2005, 10:54 PM
ahaha. Under 10 minutes...I think.
yo pusha
Dec 28 2005, 11:13 PM
thanks!!!!!!!!!!!!!!!!!!
This is a "lo-fi" version of our main content. To view the full version with more information, formatting and images, please
click here.